PEOPLE   LIVING  ON  THE  EQUATOR  ARE  CALLED  EQUESTRIANS. 

Correct answers came from  Delmar Burkitt,  Andrzej Derdzinski,  John Jackson,  Alma Litten,  Julia Minturn,  Carla Nuenke,  William Tippery,  and  Sally Yocom. 

William Tippery  also had the April cryptogram correct (my mistake).

In Puzzle #2 there were 48 households using SWOOSH detergent and 48 using Brand X. 

The correct sequence of baby snapshots in the third puzzle was 5, 6, 4, 7, 3, 2, 1.

There are many actual newspaper headlines which due to their brevity in choice of words often lead to statements which are ambiguous (often on purpose I'm afraid).  Examples are Air Head Fired or Stud Tires Out.  This month's cryptogram is one such headline and it makes it a bit harder than the usual one.  Lots of X's in this one.

X J R D M T        D B W D Y M X        X J T        X K Q C C A        P H X        W J X X D V Z D Y X        X Q C H A E        P D        P D A M D E.       

Four widows live on different floors of a tall apartment complex.  Gertrude and the coroner's widow are on adjacent floors.  The bishop's widow is four floors above Florence.  Emily and the architect's widow are ten floors apart.

There are three elevators, one stopping every third, one every fourth, and one every fifth floor.

No floor is served by all three elevators (except, of course, for floor 0).  None of the widows is served by even one elevator. 

Since none of these ladies will consent to walk upstairs, this means that when Gertrude visits the doctor's widow, she has to walk down at least four flights of stairs, no matter how often she changes elevators on the way.

What floor does Harriet live on and what did her late husband do for a living?

You have probably seen those neat calendars where the date is given by two cubes laid side by side in a box so that only the top face of each is visible.  Each face of each cube bears a number and by suitable numbering and the necessary twiddling you can make the exposed faces show any number up to the necessary 31.  Numbers below 10 are shown as 01, 02, etc., and 6 and 9 are invertible.  What is the highest number the cubes can be set to count up to without missing any numbers?  And if you have three cubes to show numbers below 100 as 001, 012, etc., what is the highest number you can count up to continuously?